What are the solutions to the equation 12x^2+75x+396=8x^2-5x-4 ?

The solutions to the equation 12x^2+75x+396=8x^2-5x-4 are x=-10

Find the zeros of 12x^2+75x+396=8x^2-5x-4

The zeros of 12x^2+75x+396=8x^2-5x-4 are x=-10

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12 x^{2} + 75 x + 396 = 8 x^{2} - 5 x - 4

x = - 10

Solution steps

12 x^{2} + 75 x + 396 = 8 x^{2} - 5 x - 4

Move

4

to the left side

12 x^{2} + 75 x + 400 = 8 x^{2} - 5 x

Move

5 x

to the left side

12 x^{2} + 80 x + 400 = 8 x^{2}

Move

8 x^{2}

to the left side

4 x^{2} + 80 x + 400 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 80 \pm 8 0 ^{2} - 4 \cdot 4 \cdot 400}{2 \cdot 4}

8 0^{2} - 4 \cdot 4 \cdot 400 = 0

x_{1, 2} = \frac{- 80 \pm 0}{2 \cdot 4}

x = \frac{- 80}{2 \cdot 4}

\frac{- 80}{2 \cdot 4} = - 10

x = - 10

The solution to the quadratic equation is:

x = - 10

x^{2} - 11 x + 1 = 0

2 y^{2} - 98 = 0

x^{2} + 164 = 16 x

p^{2} = 121

x^{2} = - 6 - 2 x

What are the solutions to the equation 12x^2+75x+396=8x^2-5x-4 ?
The solutions to the equation 12x^2+75x+396=8x^2-5x-4 are x=-10
Find the zeros of 12x^2+75x+396=8x^2-5x-4
The zeros of 12x^2+75x+396=8x^2-5x-4 are x=-10