What are the solutions to the equation factor 2x^2-5x-12=0 ?

The solutions to the equation factor 2x^2-5x-12=0 are x=-3/2 ,x=4

Find the zeros of factor 2x^2-5x-12=0

The zeros of factor 2x^2-5x-12=0 are x=-3/2 ,x=4

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2 x^{2} - 5 x - 12 = 0

x = - \frac{3}{2}, x = 4

Decimal Notation

x = - 1.5, x = 4

Solution steps

2 x^{2} - 5 x - 12 = 0

Factor

2 x^{2} - 5 x - 12 : (2 x + 3) (x - 4)

(2 x + 3) (x - 4) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

2 x + 3 = 0 or x - 4 = 0

Solve

2 x + 3 = 0 : x = - \frac{3}{2}

Solve

x - 4 = 0 : x = 4

The solutions to the quadratic equation are:

x = - \frac{3}{2}, x = 4

x^{2} - 4 x - 91 = 7

0 = 3 x^{2} - 6 x + 1

x^{2} - 9 x = - 10

1^{2} + y^{2} = 4

x^{2} - 13 x + 10 = 0

What are the solutions to the equation factor 2x^2-5x-12=0 ?
The solutions to the equation factor 2x^2-5x-12=0 are x=-3/2 ,x=4
Find the zeros of factor 2x^2-5x-12=0
The zeros of factor 2x^2-5x-12=0 are x=-3/2 ,x=4