What are the solutions to the equation x^2-20x+200=0 ?

The solutions to the equation x^2-20x+200=0 are x=10+10i,x=10-10i

Find the zeros of x^2-20x+200=0

The zeros of x^2-20x+200=0 are x=10+10i,x=10-10i

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x^{2} - 20 x + 200 = 0

x = 10 + 10 i, x = 10 - 10 i

Solution steps

x^{2} - 20 x + 200 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 20 ) \pm ( - 20 ) ^{2} - 4 \cdot 1 \cdot 200}{2 \cdot 1}

Simplify

(- 20)^{2} - 4 \cdot 1 \cdot 200 : 20 i

x_{1, 2} = \frac{- ( - 20 ) \pm 20 i}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 20 ) + 20 i}{2 \cdot 1}, x_{2} = \frac{- ( - 20 ) - 20 i}{2 \cdot 1}

x = \frac{- ( - 20 ) + 20 i}{2 \cdot 1} : 10 + 10 i

x = \frac{- ( - 20 ) - 20 i}{2 \cdot 1} : 10 - 10 i

The solutions to the quadratic equation are:

x = 10 + 10 i, x = 10 - 10 i

x^{2} + 8 x - 1 = 0

x^{2} + 17 x + 12 = 0

\frac{x ^{2}}{4} + \frac{3 x}{2} = 6

x^{2} - 3 x + 4

\frac{x ^{2}}{4} - \frac{x}{2} - 1 = 0

What are the solutions to the equation x^2-20x+200=0 ?
The solutions to the equation x^2-20x+200=0 are x=10+10i,x=10-10i
Find the zeros of x^2-20x+200=0
The zeros of x^2-20x+200=0 are x=10+10i,x=10-10i