What are the solutions to the equation (x-4)^2=-1 ?

The solutions to the equation (x-4)^2=-1 are x=i+4,x=-i+4

Find the zeros of (x-4)^2=-1

The zeros of (x-4)^2=-1 are x=i+4,x=-i+4

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(x - 4)^{2} = - 1

x = i + 4, x = - i + 4

Solution steps

(x - 4)^{2} = - 1

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x - 4 = - 1 : x = i + 4

Solve

x - 4 = - - 1 : x = - i + 4

The solutions to the quadratic equation are:

x = i + 4, x = - i + 4

(x - 4)^{2} = 19

x^{2} - 9 x + 36 = 0

2 x^{2} + 8 x + 1 = 0

x^{2} + 8 x - 9 = 0

2 x^{2} + 20 x = 0

What are the solutions to the equation (x-4)^2=-1 ?
The solutions to the equation (x-4)^2=-1 are x=i+4,x=-i+4
Find the zeros of (x-4)^2=-1
The zeros of (x-4)^2=-1 are x=i+4,x=-i+4