What are the solutions to the equation -3x^2+24x-45=0 ?

The solutions to the equation -3x^2+24x-45=0 are x=3,x=5

Find the zeros of -3x^2+24x-45=0

The zeros of -3x^2+24x-45=0 are x=3,x=5

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- 3 x^{2} + 24 x - 45 = 0

x = 3, x = 5

Solution steps

- 3 x^{2} + 24 x - 45 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 24 \pm 2 4 ^{2} - 4 ( - 3 ) ( - 45 )}{2 ( - 3 )}

2 4^{2} - 4 (- 3) (- 45) = 6

x_{1, 2} = \frac{- 24 \pm 6}{2 ( - 3 )}

Separate the solutions

x_{1} = \frac{- 24 + 6}{2 ( - 3 )}, x_{2} = \frac{- 24 - 6}{2 ( - 3 )}

x = \frac{- 24 + 6}{2 ( - 3 )} : 3

x = \frac{- 24 - 6}{2 ( - 3 )} : 5

The solutions to the quadratic equation are:

x = 3, x = 5

\frac{3 π}{4} + π

2 x + 9 \leq 7

125 n^{10}

- \frac{1}{2} - \frac{1}{2}

81 x^{2} - 1

What are the solutions to the equation -3x^2+24x-45=0 ?
The solutions to the equation -3x^2+24x-45=0 are x=3,x=5
Find the zeros of -3x^2+24x-45=0
The zeros of -3x^2+24x-45=0 are x=3,x=5