What are the solutions to the equation mx^2+(2m-3)x+m-3=0 ?

The solutions to the equation mx^2+(2m-3)x+m-3=0 are x=(-m+3)/m ,x=-1;\quad m\ne 0

Find the zeros of mx^2+(2m-3)x+m-3=0

The zeros of mx^2+(2m-3)x+m-3=0 are x=(-m+3)/m ,x=-1;\quad m\ne 0

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m x^{2} + (2 m - 3) x + m - 3 = 0

x = \frac{- m + 3}{m}, x = - 1; m \neq = 0

Solution steps

m x^{2} + (2 m - 3) x + m - 3 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( 2 m - 3 ) \pm ( 2 m - 3 ) ^{2} - 4 m ( m - 3 )}{2 m}

(2 m - 3)^{2} - 4 m (m - 3) = 3

x_{1, 2} = \frac{- ( 2 m - 3 ) \pm 3}{2 m}; m \neq = 0

Separate the solutions

x_{1} = \frac{- ( 2 m - 3 ) + 3}{2 m}, x_{2} = \frac{- ( 2 m - 3 ) - 3}{2 m}

x = \frac{- ( 2 m - 3 ) + 3}{2 m} : \frac{- m + 3}{m}

x = \frac{- ( 2 m - 3 ) - 3}{2 m} : - 1

The solutions to the quadratic equation are:

x = \frac{- m + 3}{m}, x = - 1; m \neq = 0

p, x p^{2} + (x - y) p + 1 - y = 0

15 x^{2} - 19 x + 6 = 0

x, 4 x^{2} - 3 k x + 1 = 0

2 x^{2} - 7 x = - 4

8 x^{2} + 14 x + 5 = 0

What are the solutions to the equation mx^2+(2m-3)x+m-3=0 ?
The solutions to the equation mx^2+(2m-3)x+m-3=0 are x=(-m+3)/m ,x=-1;\quad m\ne 0
Find the zeros of mx^2+(2m-3)x+m-3=0
The zeros of mx^2+(2m-3)x+m-3=0 are x=(-m+3)/m ,x=-1;\quad m\ne 0