What are the solutions to the equation x^2+5x=234 ?

The solutions to the equation x^2+5x=234 are x=13,x=-18

Find the zeros of x^2+5x=234

The zeros of x^2+5x=234 are x=13,x=-18

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x^{2} + 5 x = 234

x = 13, x = - 18

Solution steps

x^{2} + 5 x = 234

Move

234

to the left side

x^{2} + 5 x - 234 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 5 \pm 5 ^{2} - 4 \cdot 1 \cdot ( - 234 )}{2 \cdot 1}

5^{2} - 4 \cdot 1 \cdot (- 234) = 31

x_{1, 2} = \frac{- 5 \pm 31}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 5 + 31}{2 \cdot 1}, x_{2} = \frac{- 5 - 31}{2 \cdot 1}

x = \frac{- 5 + 31}{2 \cdot 1} : 13

x = \frac{- 5 - 31}{2 \cdot 1} : - 18

The solutions to the quadratic equation are:

x = 13, x = - 18

X^{2} + 10 X + 25 = 0

- 3 x^{2} + 6 x - 5

- 9 p^{2} = - 576

x, x^{2} - 4 x + 8 = 0

3 x^{2} + 2 x = 21

What are the solutions to the equation x^2+5x=234 ?
The solutions to the equation x^2+5x=234 are x=13,x=-18
Find the zeros of x^2+5x=234
The zeros of x^2+5x=234 are x=13,x=-18