What are the solutions to the equation 430=-16p^2-4p+442 ?

The solutions to the equation 430=-16p^2-4p+442 are p=-1,p= 3/4

Find the zeros of 430=-16p^2-4p+442

The zeros of 430=-16p^2-4p+442 are p=-1,p= 3/4

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430 = - 16 p^{2} - 4 p + 442

p = - 1, p = \frac{3}{4}

Decimal Notation

p = - 1, p = 0.75

Solution steps

430 = - 16 p^{2} - 4 p + 442

Switch sides

- 16 p^{2} - 4 p + 442 = 430

Move

430

to the left side

- 16 p^{2} - 4 p + 12 = 0

Solve with the quadratic formula

p_{1, 2} = \frac{- ( - 4 ) \pm ( - 4 ) ^{2} - 4 ( - 16 ) \cdot 12}{2 ( - 16 )}

(- 4)^{2} - 4 (- 16) \cdot 12 = 28

p_{1, 2} = \frac{- ( - 4 ) \pm 28}{2 ( - 16 )}

Separate the solutions

p_{1} = \frac{- ( - 4 ) + 28}{2 ( - 16 )}, p_{2} = \frac{- ( - 4 ) - 28}{2 ( - 16 )}

p = \frac{- ( - 4 ) + 28}{2 ( - 16 )} : - 1

p = \frac{- ( - 4 ) - 28}{2 ( - 16 )} : \frac{3}{4}

The solutions to the quadratic equation are:

p = - 1, p = \frac{3}{4}

x, z = 3 x^{2} - x y + 2 y^{3}

x^{2} = 2^{2} + 4^{2}

x^{2} + 2 x - 14 = 10

\frac{x ^{2}}{5} = 5

- 2 x^{2} + 16 x = - 18

What are the solutions to the equation 430=-16p^2-4p+442 ?
The solutions to the equation 430=-16p^2-4p+442 are p=-1,p= 3/4
Find the zeros of 430=-16p^2-4p+442
The zeros of 430=-16p^2-4p+442 are p=-1,p= 3/4