What are the solutions to the equation (x^2+12)=0 ?

The solutions to the equation (x^2+12)=0 are x=2sqrt(3)i,x=-2sqrt(3)i

Find the zeros of (x^2+12)=0

The zeros of (x^2+12)=0 are x=2sqrt(3)i,x=-2sqrt(3)i

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(x^{2} + 12) = 0

x = 23 i, x = - 23 i

Solution steps

(x^{2} + 12) = 0

x^{2} + 12 = 0

Move

12

to the right side

x^{2} = - 12

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = - 12, x = - - 12

- 12 = 23 i

- - 12 = - 23 i

x = 23 i, x = - 23 i

x^{2} + 3 x - 69 = - 3 x - 14

3 x - 2 = x^{2} + x - 10

- 10 q + 1000 = 0.12 q^{2} + 200

2 x^{2} = - 2 x + 5

3 x^{2} + 8 x + 3 = x

What are the solutions to the equation (x^2+12)=0 ?
The solutions to the equation (x^2+12)=0 are x=2sqrt(3)i,x=-2sqrt(3)i
Find the zeros of (x^2+12)=0
The zeros of (x^2+12)=0 are x=2sqrt(3)i,x=-2sqrt(3)i