What are the solutions to the equation 10=x^2-3x ?

The solutions to the equation 10=x^2-3x are x=5,x=-2

Find the zeros of 10=x^2-3x

The zeros of 10=x^2-3x are x=5,x=-2

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10 = x^{2} - 3 x

x = 5, x = - 2

Solution steps

10 = x^{2} - 3 x

Switch sides

x^{2} - 3 x = 10

Move

10

to the left side

x^{2} - 3 x - 10 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 3 ) \pm ( - 3 ) ^{2} - 4 \cdot 1 \cdot ( - 10 )}{2 \cdot 1}

(- 3)^{2} - 4 \cdot 1 \cdot (- 10) = 7

x_{1, 2} = \frac{- ( - 3 ) \pm 7}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 3 ) + 7}{2 \cdot 1}, x_{2} = \frac{- ( - 3 ) - 7}{2 \cdot 1}

x = \frac{- ( - 3 ) + 7}{2 \cdot 1} : 5

x = \frac{- ( - 3 ) - 7}{2 \cdot 1} : - 2

The solutions to the quadratic equation are:

x = 5, x = - 2

2 (x + 6)^{2} - 5 = 45

4 x^{2} + 3 = 9 x

(x - 3)^{2} - 5 (x - 3) - 36 = 0

25 x^{2} - 70 x + 49 = 0

2 x^{2} + 142 = - 36 x

What are the solutions to the equation 10=x^2-3x ?
The solutions to the equation 10=x^2-3x are x=5,x=-2
Find the zeros of 10=x^2-3x
The zeros of 10=x^2-3x are x=5,x=-2