What are the solutions to the equation n^2+3n+2=0 ?

The solutions to the equation n^2+3n+2=0 are n=-1,n=-2

Find the zeros of n^2+3n+2=0

The zeros of n^2+3n+2=0 are n=-1,n=-2

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n^{2} + 3 n + 2 = 0

n = - 1, n = - 2

Solution steps

n^{2} + 3 n + 2 = 0

Solve with the quadratic formula

n_{1, 2} = \frac{- 3 \pm 3 ^{2} - 4 \cdot 1 \cdot 2}{2 \cdot 1}

3^{2} - 4 \cdot 1 \cdot 2 = 1

n_{1, 2} = \frac{- 3 \pm 1}{2 \cdot 1}

Separate the solutions

n_{1} = \frac{- 3 + 1}{2 \cdot 1}, n_{2} = \frac{- 3 - 1}{2 \cdot 1}

n = \frac{- 3 + 1}{2 \cdot 1} : - 1

n = \frac{- 3 - 1}{2 \cdot 1} : - 2

The solutions to the quadratic equation are:

n = - 1, n = - 2

x, x^{2} y^{2} + 2 y^{3} = x - 2 y

y, x y^{2} - 2 x^{3} = 2

x^{2} + 15 = 7 x

(x + 5)^{2} = 10

10 x^{2} - 4 x - 17 = 6

What are the solutions to the equation n^2+3n+2=0 ?
The solutions to the equation n^2+3n+2=0 are n=-1,n=-2
Find the zeros of n^2+3n+2=0
The zeros of n^2+3n+2=0 are n=-1,n=-2