What are the solutions to the equation x^2+15x-36=0 ?

The solutions to the equation x^2+15x-36=0 are x=(-15+3sqrt(41))/2 ,x=(-15-3sqrt(41))/2

Find the zeros of x^2+15x-36=0

The zeros of x^2+15x-36=0 are x=(-15+3sqrt(41))/2 ,x=(-15-3sqrt(41))/2

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x^{2} + 15 x - 36 = 0

x = \frac{- 15 + 3 41}{2}, x = \frac{- 15 - 3 41}{2}

Decimal Notation

x = 2.10468 \dots, x = - 17.10468 \dots

Solution steps

x^{2} + 15 x - 36 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 15 \pm 1 5 ^{2} - 4 \cdot 1 \cdot ( - 36 )}{2 \cdot 1}

1 5^{2} - 4 \cdot 1 \cdot (- 36) = 341

x_{1, 2} = \frac{- 15 \pm 3 41}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 15 + 3 41}{2 \cdot 1}, x_{2} = \frac{- 15 - 3 41}{2 \cdot 1}

x = \frac{- 15 + 3 41}{2 \cdot 1} : \frac{- 15 + 3 41}{2}

x = \frac{- 15 - 3 41}{2 \cdot 1} : \frac{- 15 - 3 41}{2}

The solutions to the quadratic equation are:

x = \frac{- 15 + 3 41}{2}, x = \frac{- 15 - 3 41}{2}

6 w^{2} - 13 w + 5 = 0

r^{2} = 64

y, x^{3} + x y^{2} = 2 - 3 y

x^{2} - 2 x - 33 = 0

x^{2} - 10 x + 89 = 0

What are the solutions to the equation x^2+15x-36=0 ?
The solutions to the equation x^2+15x-36=0 are x=(-15+3sqrt(41))/2 ,x=(-15-3sqrt(41))/2
Find the zeros of x^2+15x-36=0
The zeros of x^2+15x-36=0 are x=(-15+3sqrt(41))/2 ,x=(-15-3sqrt(41))/2