What are the solutions to the equation 12a^2+6a=0 ?

The solutions to the equation 12a^2+6a=0 are a=0,a=-1/2

Find the zeros of 12a^2+6a=0

The zeros of 12a^2+6a=0 are a=0,a=-1/2

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12 a^{2} + 6 a = 0

a = 0, a = - \frac{1}{2}

Decimal Notation

a = 0, a = - 0.5

Solution steps

12 a^{2} + 6 a = 0

Solve with the quadratic formula

a_{1, 2} = \frac{- 6 \pm 6 ^{2} - 4 \cdot 12 \cdot 0}{2 \cdot 12}

6^{2} - 4 \cdot 12 \cdot 0 = 6

a_{1, 2} = \frac{- 6 \pm 6}{2 \cdot 12}

Separate the solutions

a_{1} = \frac{- 6 + 6}{2 \cdot 12}, a_{2} = \frac{- 6 - 6}{2 \cdot 12}

a = \frac{- 6 + 6}{2 \cdot 12} : 0

a = \frac{- 6 - 6}{2 \cdot 12} : - \frac{1}{2}

The solutions to the quadratic equation are:

a = 0, a = - \frac{1}{2}

- 4 x^{2} + 8 x - 1 = 0

x, f = x z - 5 x^{2} y^{3} z^{4}

z^{2} + 27 = 12 z

(x - 5) (2 x + 3) = 7

x^{2} - 1 x + 2 = 0

What are the solutions to the equation 12a^2+6a=0 ?
The solutions to the equation 12a^2+6a=0 are a=0,a=-1/2
Find the zeros of 12a^2+6a=0
The zeros of 12a^2+6a=0 are a=0,a=-1/2