What are the solutions to the equation 2x^2-12x=64 ?

The solutions to the equation 2x^2-12x=64 are x=3+sqrt(41),x=3-sqrt(41)

Find the zeros of 2x^2-12x=64

The zeros of 2x^2-12x=64 are x=3+sqrt(41),x=3-sqrt(41)

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2 x^{2} - 12 x = 64

x = 3 + 41, x = 3 - 41

Decimal Notation

x = 9.40312 \dots, x = - 3.40312 \dots

Solution steps

2 x^{2} - 12 x = 64

Move

64

to the left side

2 x^{2} - 12 x - 64 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 12 ) \pm ( - 12 ) ^{2} - 4 \cdot 2 ( - 64 )}{2 \cdot 2}

(- 12)^{2} - 4 \cdot 2 (- 64) = 441

x_{1, 2} = \frac{- ( - 12 ) \pm 4 41}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- ( - 12 ) + 4 41}{2 \cdot 2}, x_{2} = \frac{- ( - 12 ) - 4 41}{2 \cdot 2}

x = \frac{- ( - 12 ) + 4 41}{2 \cdot 2} : 3 + 41

x = \frac{- ( - 12 ) - 4 41}{2 \cdot 2} : 3 - 41

The solutions to the quadratic equation are:

x = 3 + 41, x = 3 - 41

x^{2} + 13 = 8 x + 37

x^{2} - 12 x + 36 = 44

(x + 8) (2 x - 10) = 0

x^{2} + 6 x - 9 = 0

(x - 2)^{2} = 12 (x - 2)

What are the solutions to the equation 2x^2-12x=64 ?
The solutions to the equation 2x^2-12x=64 are x=3+sqrt(41),x=3-sqrt(41)
Find the zeros of 2x^2-12x=64
The zeros of 2x^2-12x=64 are x=3+sqrt(41),x=3-sqrt(41)