What are the solutions to the equation factor 2x^2+4x-6=0 ?

The solutions to the equation factor 2x^2+4x-6=0 are x=1,x=-3

Find the zeros of factor 2x^2+4x-6=0

The zeros of factor 2x^2+4x-6=0 are x=1,x=-3

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2 x^{2} + 4 x - 6 = 0

x = 1, x = - 3

Solution steps

2 x^{2} + 4 x - 6 = 0

Factor

2 x^{2} + 4 x - 6 : 2 (x - 1) (x + 3)

2 (x - 1) (x + 3) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x - 1 = 0 or x + 3 = 0

Solve

x - 1 = 0 : x = 1

Solve

x + 3 = 0 : x = - 3

The solutions to the quadratic equation are:

x = 1, x = - 3

7 x^{2} + 23 x + 168 = 6 x^{2} + 3 x + 7

x^{2} - 5 x = 50

x^{2} + 10 x = 49

x, z = x^{2} - y^{3}

x^{2} - 18 x + 6 = 0

What are the solutions to the equation factor 2x^2+4x-6=0 ?
The solutions to the equation factor 2x^2+4x-6=0 are x=1,x=-3
Find the zeros of factor 2x^2+4x-6=0
The zeros of factor 2x^2+4x-6=0 are x=1,x=-3