What are the solutions to the equation -2x^2+50=0 ?

The solutions to the equation -2x^2+50=0 are x=5,x=-5

Find the zeros of -2x^2+50=0

The zeros of -2x^2+50=0 are x=5,x=-5

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- 2 x^{2} + 50 = 0

x = 5, x = - 5

Solution steps

- 2 x^{2} + 50 = 0

Move

50

to the right side

- 2 x^{2} = - 50

Divide both sides by

- 2

x^{2} = 25

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 25, x = - 25

25 = 5

- 25 = - 5

x = 5, x = - 5

x^{2} - 6 x + 2 = 0

7 x^{2} - 6 x - 4 = - x + 4 x^{2}

x^{2} - 6 x + 7 = 0

4 x^{2} + 4 x = 9

7 x^{2} - 38 x - 24 = 0

What are the solutions to the equation -2x^2+50=0 ?
The solutions to the equation -2x^2+50=0 are x=5,x=-5
Find the zeros of -2x^2+50=0
The zeros of -2x^2+50=0 are x=5,x=-5