What are the solutions to the equation 6x^2+x^2+1=0 ?

The solutions to the equation 6x^2+x^2+1=0 are x= 1/(sqrt(7))i,x=-1/(sqrt(7))i

Find the zeros of 6x^2+x^2+1=0

The zeros of 6x^2+x^2+1=0 are x= 1/(sqrt(7))i,x=-1/(sqrt(7))i

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6 x^{2} + x^{2} + 1 = 0

x = \frac{1}{7} i, x = - \frac{1}{7} i

Solution steps

6 x^{2} + x^{2} + 1 = 0

Move

1

to the right side

6 x^{2} + x^{2} = - 1

Add similar elements:

6 x^{2} + x^{2} = 7 x^{2}

7 x^{2} = - 1

Divide both sides by

7

x^{2} = - \frac{1}{7}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = - \frac{1}{7}, x = - - \frac{1}{7}

- \frac{1}{7} = \frac{1}{7} i

- - \frac{1}{7} = - \frac{1}{7} i

x = \frac{1}{7} i, x = - \frac{1}{7} i

5 x^{2} - 2 x = 1

2 c^{2} + 14 c + 24 = 0

x^{2} - 5 x - 11 = 0

9 n x^{2} + 12 (n + 1) x + 8 = n^{3}

(x^{2} + a x + 2) (x + 3) = (x + b) (x^{2} + c x + 6)

What are the solutions to the equation 6x^2+x^2+1=0 ?
The solutions to the equation 6x^2+x^2+1=0 are x= 1/(sqrt(7))i,x=-1/(sqrt(7))i
Find the zeros of 6x^2+x^2+1=0
The zeros of 6x^2+x^2+1=0 are x= 1/(sqrt(7))i,x=-1/(sqrt(7))i