What are the solutions to the equation 3(x+1)(x-1)=0 ?

The solutions to the equation 3(x+1)(x-1)=0 are x=-1,x=1

Find the zeros of 3(x+1)(x-1)=0

The zeros of 3(x+1)(x-1)=0 are x=-1,x=1

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3 (x + 1) (x - 1) = 0

x = - 1, x = 1

Solution steps

3 (x + 1) (x - 1) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x + 1 = 0 or x - 1 = 0

Solve

x + 1 = 0 : x = - 1

Solve

x - 1 = 0 : x = 1

The solutions to the quadratic equation are:

x = - 1, x = 1

s^{2} + 6 s + 13

5 x^{2} - x = 3

r^{2} - 3 = 0

x, x^{2} - y^{2} = 2 x y

x, 4 - y = 3 (x^{2} + z^{2})

What are the solutions to the equation 3(x+1)(x-1)=0 ?
The solutions to the equation 3(x+1)(x-1)=0 are x=-1,x=1
Find the zeros of 3(x+1)(x-1)=0
The zeros of 3(x+1)(x-1)=0 are x=-1,x=1