What are the solutions to the equation 0.6x^2+2.3x-20=0 ?

The solutions to the equation 0.6x^2+2.3x-20=0 are x= 25/6 ,x=-8

Find the zeros of 0.6x^2+2.3x-20=0

The zeros of 0.6x^2+2.3x-20=0 are x= 25/6 ,x=-8

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0.6 x^{2} + 2.3 x - 20 = 0

x = \frac{25}{6}, x = - 8

Decimal Notation

x = 4.16666 \dots, x = - 8

Solution steps

0.6 x^{2} + 2.3 x - 20 = 0

Multiply both sides by

10

6 x^{2} + 23 x - 200 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 23 \pm 2 3 ^{2} - 4 \cdot 6 ( - 200 )}{2 \cdot 6}

2 3^{2} - 4 \cdot 6 (- 200) = 73

x_{1, 2} = \frac{- 23 \pm 73}{2 \cdot 6}

Separate the solutions

x_{1} = \frac{- 23 + 73}{2 \cdot 6}, x_{2} = \frac{- 23 - 73}{2 \cdot 6}

x = \frac{- 23 + 73}{2 \cdot 6} : \frac{25}{6}

x = \frac{- 23 - 73}{2 \cdot 6} : - 8

The solutions to the quadratic equation are:

x = \frac{25}{6}, x = - 8

n^{2} - 2 n - 3 = 0

(1 - x) (4 - x) + 2 = 0

3 x^{2} + 12 x - 5 = 0

x^{2} - 9.6 x = 1.96

0 = - x^{2} - 2 x + 8

What are the solutions to the equation 0.6x^2+2.3x-20=0 ?
The solutions to the equation 0.6x^2+2.3x-20=0 are x= 25/6 ,x=-8
Find the zeros of 0.6x^2+2.3x-20=0
The zeros of 0.6x^2+2.3x-20=0 are x= 25/6 ,x=-8