What are the solutions to the equation 3y^2-2y=0 ?

The solutions to the equation 3y^2-2y=0 are y= 2/3 ,y=0

Find the zeros of 3y^2-2y=0

The zeros of 3y^2-2y=0 are y= 2/3 ,y=0

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3 y^{2} - 2 y = 0

y = \frac{2}{3}, y = 0

Decimal Notation

y = 0.66666 \dots, y = 0

Solution steps

3 y^{2} - 2 y = 0

Solve with the quadratic formula

y_{1, 2} = \frac{- ( - 2 ) \pm ( - 2 ) ^{2} - 4 \cdot 3 \cdot 0}{2 \cdot 3}

(- 2)^{2} - 4 \cdot 3 \cdot 0 = 2

y_{1, 2} = \frac{- ( - 2 ) \pm 2}{2 \cdot 3}

Separate the solutions

y_{1} = \frac{- ( - 2 ) + 2}{2 \cdot 3}, y_{2} = \frac{- ( - 2 ) - 2}{2 \cdot 3}

y = \frac{- ( - 2 ) + 2}{2 \cdot 3} : \frac{2}{3}

y = \frac{- ( - 2 ) - 2}{2 \cdot 3} : 0

The solutions to the quadratic equation are:

y = \frac{2}{3}, y = 0

6 x^{2} = 864

5 x^{2} + 10 x + 15 = 0

x^{2} + 20 x - 6 = 0

p, 3 p^{2} + 12 p = 6

s^{2} + s + 12 = 0

What are the solutions to the equation 3y^2-2y=0 ?
The solutions to the equation 3y^2-2y=0 are y= 2/3 ,y=0
Find the zeros of 3y^2-2y=0
The zeros of 3y^2-2y=0 are y= 2/3 ,y=0