What are the solutions to the equation k^2+3k-2=0 ?

The solutions to the equation k^2+3k-2=0 are k=(-3+sqrt(17))/2 ,k=(-3-sqrt(17))/2

Find the zeros of k^2+3k-2=0

The zeros of k^2+3k-2=0 are k=(-3+sqrt(17))/2 ,k=(-3-sqrt(17))/2

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k^{2} + 3 k - 2 = 0

k = \frac{- 3 + 17}{2}, k = \frac{- 3 - 17}{2}

Decimal Notation

k = 0.56155 \dots, k = - 3.56155 \dots

Solution steps

k^{2} + 3 k - 2 = 0

Solve with the quadratic formula

k_{1, 2} = \frac{- 3 \pm 3 ^{2} - 4 \cdot 1 \cdot ( - 2 )}{2 \cdot 1}

3^{2} - 4 \cdot 1 \cdot (- 2) = 17

k_{1, 2} = \frac{- 3 \pm 17}{2 \cdot 1}

Separate the solutions

k_{1} = \frac{- 3 + 17}{2 \cdot 1}, k_{2} = \frac{- 3 - 17}{2 \cdot 1}

k = \frac{- 3 + 17}{2 \cdot 1} : \frac{- 3 + 17}{2}

k = \frac{- 3 - 17}{2 \cdot 1} : \frac{- 3 - 17}{2}

The solutions to the quadratic equation are:

k = \frac{- 3 + 17}{2}, k = \frac{- 3 - 17}{2}

6 x^{2} = 24 x

12 x^{2} - 18 x - 12 = 0

12 x^{2} + 8 x - 8 = 0

12 x^{2} - 18 x + 6 = 0

x, x^{2} - y x - x + y - 1 = 0

What are the solutions to the equation k^2+3k-2=0 ?
The solutions to the equation k^2+3k-2=0 are k=(-3+sqrt(17))/2 ,k=(-3-sqrt(17))/2
Find the zeros of k^2+3k-2=0
The zeros of k^2+3k-2=0 are k=(-3+sqrt(17))/2 ,k=(-3-sqrt(17))/2