What are the solutions to the equation z^2-2z+10=0 ?

The solutions to the equation z^2-2z+10=0 are z=1+3i,z=1-3i

Find the zeros of z^2-2z+10=0

The zeros of z^2-2z+10=0 are z=1+3i,z=1-3i

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z^{2} - 2 z + 10 = 0

z = 1 + 3 i, z = 1 - 3 i

Solution steps

z^{2} - 2 z + 10 = 0

Solve with the quadratic formula

z_{1, 2} = \frac{- ( - 2 ) \pm ( - 2 ) ^{2} - 4 \cdot 1 \cdot 10}{2 \cdot 1}

Simplify

(- 2)^{2} - 4 \cdot 1 \cdot 10 : 6 i

z_{1, 2} = \frac{- ( - 2 ) \pm 6 i}{2 \cdot 1}

Separate the solutions

z_{1} = \frac{- ( - 2 ) + 6 i}{2 \cdot 1}, z_{2} = \frac{- ( - 2 ) - 6 i}{2 \cdot 1}

z = \frac{- ( - 2 ) + 6 i}{2 \cdot 1} : 1 + 3 i

z = \frac{- ( - 2 ) - 6 i}{2 \cdot 1} : 1 - 3 i

The solutions to the quadratic equation are:

z = 1 + 3 i, z = 1 - 3 i

x^{2} + 17 x + 66 = 0

2 x^{2} - x = - 5

x, (x^{2}) + (x^{2}) = (y^{2})

2 x^{2} - 12 x + 19

3 x^{2} + 7 x = 0

What are the solutions to the equation z^2-2z+10=0 ?
The solutions to the equation z^2-2z+10=0 are z=1+3i,z=1-3i
Find the zeros of z^2-2z+10=0
The zeros of z^2-2z+10=0 are z=1+3i,z=1-3i