What are the solutions to the equation (x)=x^2+6x+8 ?

The solutions to the equation (x)=x^2+6x+8 are x=-5/2+i(sqrt(7))/2 ,x=-5/2-i(sqrt(7))/2

Find the zeros of (x)=x^2+6x+8

The zeros of (x)=x^2+6x+8 are x=-5/2+i(sqrt(7))/2 ,x=-5/2-i(sqrt(7))/2

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(x) = x^{2} + 6 x + 8

x = - \frac{5}{2} + i \frac{7}{2}, x = - \frac{5}{2} - i \frac{7}{2}

Solution steps

(x) = x^{2} + 6 x + 8

Refine

x = x^{2} + 6 x + 8

Switch sides

x^{2} + 6 x + 8 = x

Move

x

to the left side

x^{2} + 5 x + 8 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 5 \pm 5 ^{2} - 4 \cdot 1 \cdot 8}{2 \cdot 1}

Simplify

5^{2} - 4 \cdot 1 \cdot 8 : 7 i

x_{1, 2} = \frac{- 5 \pm 7 i}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 5 + 7 i}{2 \cdot 1}, x_{2} = \frac{- 5 - 7 i}{2 \cdot 1}

x = \frac{- 5 + 7 i}{2 \cdot 1} : - \frac{5}{2} + i \frac{7}{2}

x = \frac{- 5 - 7 i}{2 \cdot 1} : - \frac{5}{2} - i \frac{7}{2}

The solutions to the quadratic equation are:

x = - \frac{5}{2} + i \frac{7}{2}, x = - \frac{5}{2} - i \frac{7}{2}

p^{2} - 121 = 0

x^{2} - 14 x - 11 = 0

x^{2} + 3 x - 1

0.25 x^{2} - 1.5 x - 7 = 0

- 3 x^{2} = - 3

What are the solutions to the equation (x)=x^2+6x+8 ?
The solutions to the equation (x)=x^2+6x+8 are x=-5/2+i(sqrt(7))/2 ,x=-5/2-i(sqrt(7))/2
Find the zeros of (x)=x^2+6x+8
The zeros of (x)=x^2+6x+8 are x=-5/2+i(sqrt(7))/2 ,x=-5/2-i(sqrt(7))/2