What are the solutions to the equation x^2-2x-4=-2x+5-2x+5 ?

The solutions to the equation x^2-2x-4=-2x+5-2x+5 are x=-1+sqrt(15),x=-1-sqrt(15)

Find the zeros of x^2-2x-4=-2x+5-2x+5

The zeros of x^2-2x-4=-2x+5-2x+5 are x=-1+sqrt(15),x=-1-sqrt(15)

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x^{2} - 2 x - 4 = - 2 x + 5 - 2 x + 5

x = - 1 + 15, x = - 1 - 15

Decimal Notation

x = 2.87298 \dots, x = - 4.87298 \dots

Solution steps

x^{2} - 2 x - 4 = - 2 x + 5 - 2 x + 5

Refine

x^{2} - 2 x - 4 = - 4 x + 10

Move

10

to the left side

x^{2} - 2 x - 14 = - 4 x

Move

4 x

to the left side

x^{2} + 2 x - 14 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 2 \pm 2 ^{2} - 4 \cdot 1 \cdot ( - 14 )}{2 \cdot 1}

2^{2} - 4 \cdot 1 \cdot (- 14) = 215

x_{1, 2} = \frac{- 2 \pm 2 15}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 2 + 2 15}{2 \cdot 1}, x_{2} = \frac{- 2 - 2 15}{2 \cdot 1}

x = \frac{- 2 + 2 15}{2 \cdot 1} : - 1 + 15

x = \frac{- 2 - 2 15}{2 \cdot 1} : - 1 - 15

The solutions to the quadratic equation are:

x = - 1 + 15, x = - 1 - 15

1 - x^{2} = 1 - x

5 x^{2} = 7 x

x^{2} + x + 36 = 0

4 x^{2} = 16 x + 25

6 x - 5 = x^{2}

What are the solutions to the equation x^2-2x-4=-2x+5-2x+5 ?
The solutions to the equation x^2-2x-4=-2x+5-2x+5 are x=-1+sqrt(15),x=-1-sqrt(15)
Find the zeros of x^2-2x-4=-2x+5-2x+5
The zeros of x^2-2x-4=-2x+5-2x+5 are x=-1+sqrt(15),x=-1-sqrt(15)