What are the solutions to the equation 7v^2=89-14v ?

The solutions to the equation 7v^2=89-14v are v=(-7+4sqrt(42))/7 ,v=-(7+4sqrt(42))/7

Find the zeros of 7v^2=89-14v

The zeros of 7v^2=89-14v are v=(-7+4sqrt(42))/7 ,v=-(7+4sqrt(42))/7

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7 v^{2} = 89 - 14 v

v = \frac{- 7 + 4 42}{7}, v = - \frac{7 + 4 42}{7}

Decimal Notation

v = 2.70328 \dots, v = - 4.70328 \dots

Solution steps

7 v^{2} = 89 - 14 v

Move

14 v

to the left side

7 v^{2} + 14 v = 89

Move

89

to the left side

7 v^{2} + 14 v - 89 = 0

Solve with the quadratic formula

v_{1, 2} = \frac{- 14 \pm 1 4 ^{2} - 4 \cdot 7 ( - 89 )}{2 \cdot 7}

1 4^{2} - 4 \cdot 7 (- 89) = 842

v_{1, 2} = \frac{- 14 \pm 8 42}{2 \cdot 7}

Separate the solutions

v_{1} = \frac{- 14 + 8 42}{2 \cdot 7}, v_{2} = \frac{- 14 - 8 42}{2 \cdot 7}

v = \frac{- 14 + 8 42}{2 \cdot 7} : \frac{- 7 + 4 42}{7}

v = \frac{- 14 - 8 42}{2 \cdot 7} : - \frac{7 + 4 42}{7}

The solutions to the quadratic equation are:

v = \frac{- 7 + 4 42}{7}, v = - \frac{7 + 4 42}{7}

2 x^{2} + 11 x - 30 = 0

- 3 x^{2} - 42 x - 120 = 0

- 3 x^{2} + 12 x + 3 = 0

4 a^{2} - 36 = 0

x^{2} - 7 x + 12 = 2

What are the solutions to the equation 7v^2=89-14v ?
The solutions to the equation 7v^2=89-14v are v=(-7+4sqrt(42))/7 ,v=-(7+4sqrt(42))/7
Find the zeros of 7v^2=89-14v
The zeros of 7v^2=89-14v are v=(-7+4sqrt(42))/7 ,v=-(7+4sqrt(42))/7