What are the solutions to the equation 49x^2+84x+36=0 ?

The solutions to the equation 49x^2+84x+36=0 are x=-6/7

Find the zeros of 49x^2+84x+36=0

The zeros of 49x^2+84x+36=0 are x=-6/7

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49 x^{2} + 84 x + 36 = 0

x = - \frac{6}{7}

Decimal Notation

x = - 0.85714 \dots

Solution steps

49 x^{2} + 84 x + 36 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 84 \pm 8 4 ^{2} - 4 \cdot 49 \cdot 36}{2 \cdot 49}

8 4^{2} - 4 \cdot 49 \cdot 36 = 0

x_{1, 2} = \frac{- 84 \pm 0}{2 \cdot 49}

x = \frac{- 84}{2 \cdot 49}

\frac{- 84}{2 \cdot 49} = - \frac{6}{7}

x = - \frac{6}{7}

The solution to the quadratic equation is:

x = - \frac{6}{7}

x^{2} + (- \frac{1}{3})^{2} = 1

12.38 x^{2} - 28.6 x + 12.38 = 0

2 r^{2} - 3 r + 1 = 0

x^{2} = 2 4^{2} + 1 0^{2}

x = x^{2} - 2 x

What are the solutions to the equation 49x^2+84x+36=0 ?
The solutions to the equation 49x^2+84x+36=0 are x=-6/7
Find the zeros of 49x^2+84x+36=0
The zeros of 49x^2+84x+36=0 are x=-6/7