What are the solutions to the equation x^2-2x=2x-4 ?

The solutions to the equation x^2-2x=2x-4 are x=2

Find the zeros of x^2-2x=2x-4

The zeros of x^2-2x=2x-4 are x=2

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x^{2} - 2 x = 2 x - 4

x = 2

Solution steps

x^{2} - 2 x = 2 x - 4

Move

4

to the left side

x^{2} - 2 x + 4 = 2 x

Move

2 x

to the left side

x^{2} - 4 x + 4 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 4 ) \pm ( - 4 ) ^{2} - 4 \cdot 1 \cdot 4}{2 \cdot 1}

(- 4)^{2} - 4 \cdot 1 \cdot 4 = 0

x_{1, 2} = \frac{- ( - 4 ) \pm 0}{2 \cdot 1}

x = \frac{- ( - 4 )}{2 \cdot 1}

\frac{- ( - 4 )}{2 \cdot 1} = 2

x = 2

The solution to the quadratic equation is:

x = 2

x^{2} + 7 x + 6 = 14

4 y^{2} + 8 y + 3 = 0

3 x^{2} - 9 x - 1 = 0

5 x^{2} + 7 x - 3 = 0

t^{2} = 20

What are the solutions to the equation x^2-2x=2x-4 ?
The solutions to the equation x^2-2x=2x-4 are x=2
Find the zeros of x^2-2x=2x-4
The zeros of x^2-2x=2x-4 are x=2