What are the solutions to the equation solvefor x,f=(y-3x)^2 ?

The solutions to the equation solvefor x,f=(y-3x)^2 are x=-(sqrt(f)-y)/3 ,x=-(-sqrt(f)-y)/3

Find the zeros of solvefor x,f=(y-3x)^2

The zeros of solvefor x,f=(y-3x)^2 are x=-(sqrt(f)-y)/3 ,x=-(-sqrt(f)-y)/3

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solve for

x, f = (y - 3 x)^{2}

x = - \frac{f - y}{3}, x = - \frac{- f - y}{3}

Solution steps

f = (y - 3 x)^{2}

Switch sides

(y - 3 x)^{2} = f

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

y - 3 x = f : x = - \frac{f - y}{3}

Solve

y - 3 x = - f : x = - \frac{- f - y}{3}

The solutions to the quadratic equation are:

x = - \frac{f - y}{3}, x = - \frac{- f - y}{3}

t^{2} - 50 = 0

x, 2 x^{2} - x - 1 = 0

- x^{2} - 5 x + 6 = 2 x^{2} + 4 x - 11

x^{2} - 9 x + \frac{81}{4} = \frac{1}{4}

0.5 x + 6 = 2 (2 x - 3) x

What are the solutions to the equation solvefor x,f=(y-3x)^2 ?
The solutions to the equation solvefor x,f=(y-3x)^2 are x=-(sqrt(f)-y)/3 ,x=-(-sqrt(f)-y)/3
Find the zeros of solvefor x,f=(y-3x)^2
The zeros of solvefor x,f=(y-3x)^2 are x=-(sqrt(f)-y)/3 ,x=-(-sqrt(f)-y)/3