What are the solutions to the equation 8x^2=12-4x ?

The solutions to the equation 8x^2=12-4x are x=1,x=-3/2

Find the zeros of 8x^2=12-4x

The zeros of 8x^2=12-4x are x=1,x=-3/2

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8 x^{2} = 12 - 4 x

x = 1, x = - \frac{3}{2}

Decimal Notation

x = 1, x = - 1.5

Solution steps

8 x^{2} = 12 - 4 x

Move

4 x

to the left side

8 x^{2} + 4 x = 12

Move

12

to the left side

8 x^{2} + 4 x - 12 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 \cdot 8 ( - 12 )}{2 \cdot 8}

4^{2} - 4 \cdot 8 (- 12) = 20

x_{1, 2} = \frac{- 4 \pm 20}{2 \cdot 8}

Separate the solutions

x_{1} = \frac{- 4 + 20}{2 \cdot 8}, x_{2} = \frac{- 4 - 20}{2 \cdot 8}

x = \frac{- 4 + 20}{2 \cdot 8} : 1

x = \frac{- 4 - 20}{2 \cdot 8} : - \frac{3}{2}

The solutions to the quadratic equation are:

x = 1, x = - \frac{3}{2}

s^{2} - 2 s + 10

x, 5 x^{2} - 3 x y + 5 y^{2} - 27 = 0

x^{2} - 2 x - 48 = 0

2 y - 3 y^{2} + 1 = 0

x^{2} + 2 x + 17

What are the solutions to the equation 8x^2=12-4x ?
The solutions to the equation 8x^2=12-4x are x=1,x=-3/2
Find the zeros of 8x^2=12-4x
The zeros of 8x^2=12-4x are x=1,x=-3/2