What are the solutions to the equation 9x^2-16x+52=8x^2 ?

The solutions to the equation 9x^2-16x+52=8x^2 are x=2(4+sqrt(3)),x=2(4-sqrt(3))

Find the zeros of 9x^2-16x+52=8x^2

The zeros of 9x^2-16x+52=8x^2 are x=2(4+sqrt(3)),x=2(4-sqrt(3))

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9 x^{2} - 16 x + 52 = 8 x^{2}

x = 2 (4 + 3), x = 2 (4 - 3)

Decimal Notation

x = 11.46410 \dots, x = 4.53589 \dots

Solution steps

9 x^{2} - 16 x + 52 = 8 x^{2}

Move

8 x^{2}

to the left side

x^{2} - 16 x + 52 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 16 ) \pm ( - 16 ) ^{2} - 4 \cdot 1 \cdot 52}{2 \cdot 1}

(- 16)^{2} - 4 \cdot 1 \cdot 52 = 43

x_{1, 2} = \frac{- ( - 16 ) \pm 4 3}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 16 ) + 4 3}{2 \cdot 1}, x_{2} = \frac{- ( - 16 ) - 4 3}{2 \cdot 1}

x = \frac{- ( - 16 ) + 4 3}{2 \cdot 1} : 2 (4 + 3)

x = \frac{- ( - 16 ) - 4 3}{2 \cdot 1} : 2 (4 - 3)

The solutions to the quadratic equation are:

x = 2 (4 + 3), x = 2 (4 - 3)

(2 x + 5) (x - 3) = 0

192 = π r^{2} h

- 100 x^{2} + 160 x - 64 = 0

- x^{2} - 6 x + 7

y, y^{2} = 4 x

What are the solutions to the equation 9x^2-16x+52=8x^2 ?
The solutions to the equation 9x^2-16x+52=8x^2 are x=2(4+sqrt(3)),x=2(4-sqrt(3))
Find the zeros of 9x^2-16x+52=8x^2
The zeros of 9x^2-16x+52=8x^2 are x=2(4+sqrt(3)),x=2(4-sqrt(3))