What are the solutions to the equation 0=-x^2-x+6 ?

The solutions to the equation 0=-x^2-x+6 are x=-3,x=2

Find the zeros of 0=-x^2-x+6

The zeros of 0=-x^2-x+6 are x=-3,x=2

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0 = - x^{2} - x + 6

x = - 3, x = 2

Solution steps

0 = - x^{2} - x + 6

Switch sides

- x^{2} - x + 6 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 1 ) \pm ( - 1 ) ^{2} - 4 ( - 1 ) \cdot 6}{2 ( - 1 )}

(- 1)^{2} - 4 (- 1) \cdot 6 = 5

x_{1, 2} = \frac{- ( - 1 ) \pm 5}{2 ( - 1 )}

Separate the solutions

x_{1} = \frac{- ( - 1 ) + 5}{2 ( - 1 )}, x_{2} = \frac{- ( - 1 ) - 5}{2 ( - 1 )}

x = \frac{- ( - 1 ) + 5}{2 ( - 1 )} : - 3

x = \frac{- ( - 1 ) - 5}{2 ( - 1 )} : 2

The solutions to the quadratic equation are:

x = - 3, x = 2

π r^{2} h = 35.257, r

4 - 6 (x - 5)^{2} = 0

2 (x - 3)^{2} = - 2 x + 9

x^{2} + 5 x + 6

x^{2} + (x + 2)^{2} = 202

What are the solutions to the equation 0=-x^2-x+6 ?
The solutions to the equation 0=-x^2-x+6 are x=-3,x=2
Find the zeros of 0=-x^2-x+6
The zeros of 0=-x^2-x+6 are x=-3,x=2