What are the solutions to the equation 4m^2+96=-40m ?

The solutions to the equation 4m^2+96=-40m are m=-4,m=-6

Find the zeros of 4m^2+96=-40m

The zeros of 4m^2+96=-40m are m=-4,m=-6

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4 m^{2} + 96 = - 40 m

m = - 4, m = - 6

Solution steps

4 m^{2} + 96 = - 40 m

Move

40 m

to the left side

4 m^{2} + 96 + 40 m = 0

Write in the standard form

a x^{2} + b x + c = 0

4 m^{2} + 40 m + 96 = 0

Solve with the quadratic formula

m_{1, 2} = \frac{- 40 \pm 4 0 ^{2} - 4 \cdot 4 \cdot 96}{2 \cdot 4}

4 0^{2} - 4 \cdot 4 \cdot 96 = 8

m_{1, 2} = \frac{- 40 \pm 8}{2 \cdot 4}

Separate the solutions

m_{1} = \frac{- 40 + 8}{2 \cdot 4}, m_{2} = \frac{- 40 - 8}{2 \cdot 4}

m = \frac{- 40 + 8}{2 \cdot 4} : - 4

m = \frac{- 40 - 8}{2 \cdot 4} : - 6

The solutions to the quadratic equation are:

m = - 4, m = - 6

v^{2} + 3 v - 18 = 0

(20 + x) (20000 - 500 x) = 425000

0 = 3 x^{2} + 6 x - 9

2 b^{2} - b - 1 = 0

2 x^{2} + (x - 2) (x + 5) = (x + 3) (x - 4)

What are the solutions to the equation 4m^2+96=-40m ?
The solutions to the equation 4m^2+96=-40m are m=-4,m=-6
Find the zeros of 4m^2+96=-40m
The zeros of 4m^2+96=-40m are m=-4,m=-6