What are the solutions to the equation y^2+4y-6=0 ?

The solutions to the equation y^2+4y-6=0 are y=-2+sqrt(10),y=-2-sqrt(10)

Find the zeros of y^2+4y-6=0

The zeros of y^2+4y-6=0 are y=-2+sqrt(10),y=-2-sqrt(10)

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y^{2} + 4 y - 6 = 0

y = - 2 + 10, y = - 2 - 10

Decimal Notation

y = 1.16227 \dots, y = - 5.16227 \dots

Solution steps

y^{2} + 4 y - 6 = 0

Solve with the quadratic formula

y_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 \cdot 1 \cdot ( - 6 )}{2 \cdot 1}

4^{2} - 4 \cdot 1 \cdot (- 6) = 210

y_{1, 2} = \frac{- 4 \pm 2 10}{2 \cdot 1}

Separate the solutions

y_{1} = \frac{- 4 + 2 10}{2 \cdot 1}, y_{2} = \frac{- 4 - 2 10}{2 \cdot 1}

y = \frac{- 4 + 2 10}{2 \cdot 1} : - 2 + 10

y = \frac{- 4 - 2 10}{2 \cdot 1} : - 2 - 10

The solutions to the quadratic equation are:

y = - 2 + 10, y = - 2 - 10

12 x^{2} - 288 x + 1152 = 0

(X + 6) (X - 6) = 13

x^{2} + 17 x + 12 = 0

23 x = - 15 x^{2} - 6

x^{2} - 16 x + 40 = 0

What are the solutions to the equation y^2+4y-6=0 ?
The solutions to the equation y^2+4y-6=0 are y=-2+sqrt(10),y=-2-sqrt(10)
Find the zeros of y^2+4y-6=0
The zeros of y^2+4y-6=0 are y=-2+sqrt(10),y=-2-sqrt(10)