What are the solutions to the equation 0=3x^2+8x-11 ?

The solutions to the equation 0=3x^2+8x-11 are x=1,x=-11/3

Find the zeros of 0=3x^2+8x-11

The zeros of 0=3x^2+8x-11 are x=1,x=-11/3

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0 = 3 x^{2} + 8 x - 11

x = 1, x = - \frac{11}{3}

Decimal Notation

x = 1, x = - 3.66666 \dots

Solution steps

0 = 3 x^{2} + 8 x - 11

Switch sides

3 x^{2} + 8 x - 11 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 8 \pm 8 ^{2} - 4 \cdot 3 ( - 11 )}{2 \cdot 3}

8^{2} - 4 \cdot 3 (- 11) = 14

x_{1, 2} = \frac{- 8 \pm 14}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- 8 + 14}{2 \cdot 3}, x_{2} = \frac{- 8 - 14}{2 \cdot 3}

x = \frac{- 8 + 14}{2 \cdot 3} : 1

x = \frac{- 8 - 14}{2 \cdot 3} : - \frac{11}{3}

The solutions to the quadratic equation are:

x = 1, x = - \frac{11}{3}

2 x^{2} - 5 x = - 9

2 x^{2} - 5 x = 2 x

y, x y + y^{2} = 2

t^{2} - 5 t - 36 = 0

x^{2} + x^{2} = 4^{2}

What are the solutions to the equation 0=3x^2+8x-11 ?
The solutions to the equation 0=3x^2+8x-11 are x=1,x=-11/3
Find the zeros of 0=3x^2+8x-11
The zeros of 0=3x^2+8x-11 are x=1,x=-11/3