What are the solutions to the equation x^2-14x-48=0 ?

The solutions to the equation x^2-14x-48=0 are x=7+sqrt(97),x=7-sqrt(97)

Find the zeros of x^2-14x-48=0

The zeros of x^2-14x-48=0 are x=7+sqrt(97),x=7-sqrt(97)

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x^{2} - 14 x - 48 = 0

x = 7 + 97, x = 7 - 97

Decimal Notation

x = 16.84885 \dots, x = - 2.84885 \dots

Solution steps

x^{2} - 14 x - 48 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 14 ) \pm ( - 14 ) ^{2} - 4 \cdot 1 \cdot ( - 48 )}{2 \cdot 1}

(- 14)^{2} - 4 \cdot 1 \cdot (- 48) = 297

x_{1, 2} = \frac{- ( - 14 ) \pm 2 97}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 14 ) + 2 97}{2 \cdot 1}, x_{2} = \frac{- ( - 14 ) - 2 97}{2 \cdot 1}

x = \frac{- ( - 14 ) + 2 97}{2 \cdot 1} : 7 + 97

x = \frac{- ( - 14 ) - 2 97}{2 \cdot 1} : 7 - 97

The solutions to the quadratic equation are:

x = 7 + 97, x = 7 - 97

x^{2} + 4 x + 2

x^{2} + 4 x - 6

x^{2} - 2 x + 1 = 0

- 0.3 x^{2} + 70 = 0.1 x^{2} + x + 20

- (x + 2) (x - 1) = 3

What are the solutions to the equation x^2-14x-48=0 ?
The solutions to the equation x^2-14x-48=0 are x=7+sqrt(97),x=7-sqrt(97)
Find the zeros of x^2-14x-48=0
The zeros of x^2-14x-48=0 are x=7+sqrt(97),x=7-sqrt(97)