What are the solutions to the equation (4x+14)^2=12 ?

The solutions to the equation (4x+14)^2=12 are x=(sqrt(3)-7)/2 ,x=-(7+sqrt(3))/2

Find the zeros of (4x+14)^2=12

The zeros of (4x+14)^2=12 are x=(sqrt(3)-7)/2 ,x=-(7+sqrt(3))/2

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(4 x + 14)^{2} = 12

x = \frac{3 - 7}{2}, x = - \frac{7 + 3}{2}

Decimal Notation

x = - 2.63397 \dots, x = - 4.36602 \dots

Solution steps

(4 x + 14)^{2} = 12

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

4 x + 14 = 12 : x = \frac{3 - 7}{2}

Solve

4 x + 14 = - 12 : x = - \frac{7 + 3}{2}

The solutions to the quadratic equation are:

x = \frac{3 - 7}{2}, x = - \frac{7 + 3}{2}

y, (x - 2)^{2} + y^{2} = 4

x^{2} - 16 = - 2 x - 1 - 2 x - 1

5 x^{2} - 6 x = 3

(2 d + 3)^{2} = 36

- 3 x^{2} + 30 x + 72 = 0

What are the solutions to the equation (4x+14)^2=12 ?
The solutions to the equation (4x+14)^2=12 are x=(sqrt(3)-7)/2 ,x=-(7+sqrt(3))/2
Find the zeros of (4x+14)^2=12
The zeros of (4x+14)^2=12 are x=(sqrt(3)-7)/2 ,x=-(7+sqrt(3))/2