What are the solutions to the equation 0=-16x^2+64x+48 ?

The solutions to the equation 0=-16x^2+64x+48 are x=2-sqrt(7),x=2+sqrt(7)

Find the zeros of 0=-16x^2+64x+48

The zeros of 0=-16x^2+64x+48 are x=2-sqrt(7),x=2+sqrt(7)

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0 = - 16 x^{2} + 64 x + 48

x = 2 - 7, x = 2 + 7

Decimal Notation

x = - 0.64575 \dots, x = 4.64575 \dots

Solution steps

0 = - 16 x^{2} + 64 x + 48

Switch sides

- 16 x^{2} + 64 x + 48 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 64 \pm 6 4 ^{2} - 4 ( - 16 ) \cdot 48}{2 ( - 16 )}

6 4^{2} - 4 (- 16) \cdot 48 = 327

x_{1, 2} = \frac{- 64 \pm 32 7}{2 ( - 16 )}

Separate the solutions

x_{1} = \frac{- 64 + 32 7}{2 ( - 16 )}, x_{2} = \frac{- 64 - 32 7}{2 ( - 16 )}

x = \frac{- 64 + 32 7}{2 ( - 16 )} : 2 - 7

x = \frac{- 64 - 32 7}{2 ( - 16 )} : 2 + 7

The solutions to the quadratic equation are:

x = 2 - 7, x = 2 + 7

4 (4 x - 3)^{2} - 10 = 26

x^{2} + 11 x + 50 = 20

4 x^{2} - 13 x = - 3

s (s + 1) = 0

5 x^{2} - 10 x + 3 = 0

What are the solutions to the equation 0=-16x^2+64x+48 ?
The solutions to the equation 0=-16x^2+64x+48 are x=2-sqrt(7),x=2+sqrt(7)
Find the zeros of 0=-16x^2+64x+48
The zeros of 0=-16x^2+64x+48 are x=2-sqrt(7),x=2+sqrt(7)