What are the solutions to the equation x^2-22x+102=0 ?

The solutions to the equation x^2-22x+102=0 are x=11+sqrt(19),x=11-sqrt(19)

Find the zeros of x^2-22x+102=0

The zeros of x^2-22x+102=0 are x=11+sqrt(19),x=11-sqrt(19)

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x^{2} - 22 x + 102 = 0

x = 11 + 19, x = 11 - 19

Decimal Notation

x = 15.35889 \dots, x = 6.64110 \dots

Solution steps

x^{2} - 22 x + 102 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 22 ) \pm ( - 22 ) ^{2} - 4 \cdot 1 \cdot 102}{2 \cdot 1}

(- 22)^{2} - 4 \cdot 1 \cdot 102 = 219

x_{1, 2} = \frac{- ( - 22 ) \pm 2 19}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 22 ) + 2 19}{2 \cdot 1}, x_{2} = \frac{- ( - 22 ) - 2 19}{2 \cdot 1}

x = \frac{- ( - 22 ) + 2 19}{2 \cdot 1} : 11 + 19

x = \frac{- ( - 22 ) - 2 19}{2 \cdot 1} : 11 - 19

The solutions to the quadratic equation are:

x = 11 + 19, x = 11 - 19

(x - 3)^{2} + (- x + 7)^{2} = 16

x^{2} + 2 x - \frac{5}{4} = 0

5^{2} + x^{2} = 9^{2}

x, 3 x^{2} + 4 x y + 6 y^{2} = 140

x^{2} - 21 = - 38

What are the solutions to the equation x^2-22x+102=0 ?
The solutions to the equation x^2-22x+102=0 are x=11+sqrt(19),x=11-sqrt(19)
Find the zeros of x^2-22x+102=0
The zeros of x^2-22x+102=0 are x=11+sqrt(19),x=11-sqrt(19)