What are the solutions to the equation sqrt(6)x^2+2x-sqrt(3/2)=0 ?

The solutions to the equation sqrt(6)x^2+2x-sqrt(3/2)=0 are x= 1/(sqrt(6)),x=-sqrt(3/2)

Find the zeros of sqrt(6)x^2+2x-sqrt(3/2)=0

The zeros of sqrt(6)x^2+2x-sqrt(3/2)=0 are x= 1/(sqrt(6)),x=-sqrt(3/2)

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6 x^{2} + 2 x - \frac{3}{2} = 0

x = \frac{1}{6}, x = - \frac{3}{2}

Decimal Notation

x = 0.40824 \dots, x = - 1.22474 \dots

Solution steps

6 x^{2} + 2 x - \frac{3}{2} = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 2 \pm 2 ^{2} - 4 6 ( - \frac{3}{2} )}{2 6}

2^{2} - 46 (- \frac{3}{2}) = 4

x_{1, 2} = \frac{- 2 \pm 4}{2 6}

Separate the solutions

x_{1} = \frac{- 2 + 4}{2 6}, x_{2} = \frac{- 2 - 4}{2 6}

x = \frac{- 2 + 4}{2 6} : \frac{1}{6}

x = \frac{- 2 - 4}{2 6} : - \frac{3}{2}

The solutions to the quadratic equation are:

x = \frac{1}{6}, x = - \frac{3}{2}

12 x^{2} - 64 x + 64 = 0

3 x - x^{2} = x - 3

2 (5 x - 3)^{2} + 14 = 16

x, x^{2} + 2 y^{2} = 0

x^{2} + 16 x = 36

What are the solutions to the equation sqrt(6)x^2+2x-sqrt(3/2)=0 ?
The solutions to the equation sqrt(6)x^2+2x-sqrt(3/2)=0 are x= 1/(sqrt(6)),x=-sqrt(3/2)
Find the zeros of sqrt(6)x^2+2x-sqrt(3/2)=0
The zeros of sqrt(6)x^2+2x-sqrt(3/2)=0 are x= 1/(sqrt(6)),x=-sqrt(3/2)