What are the solutions to the equation 25-70X+49X^2=0 ?

The solutions to the equation 25-70X+49X^2=0 are X= 5/7

Find the zeros of 25-70X+49X^2=0

The zeros of 25-70X+49X^2=0 are X= 5/7

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25 - 70 X + 49 X^{2} = 0

X = \frac{5}{7}

Decimal Notation

X = 0.71428 \dots

Solution steps

25 - 70 X + 49 X^{2} = 0

Write in the standard form

a x^{2} + b x + c = 0

49 X^{2} - 70 X + 25 = 0

Solve with the quadratic formula

X_{1, 2} = \frac{- ( - 70 ) \pm ( - 70 ) ^{2} - 4 \cdot 49 \cdot 25}{2 \cdot 49}

(- 70)^{2} - 4 \cdot 49 \cdot 25 = 0

X_{1, 2} = \frac{- ( - 70 ) \pm 0}{2 \cdot 49}

X = \frac{- ( - 70 )}{2 \cdot 49}

\frac{- ( - 70 )}{2 \cdot 49} = \frac{5}{7}

X = \frac{5}{7}

The solution to the quadratic equation is:

X = \frac{5}{7}

x, \frac{x ^{2}}{25} - \frac{y ^{2}}{16} = 0

x, 8 x^{2} + 4 x y + 5 y^{2} + 2 y - 14 = 0

3 x^{2} + 3 x - 8 = 2 x^{2} + x + 7

x^{2} - 3 x = - 4

x^{2} - 3 x = 2 x

What are the solutions to the equation 25-70X+49X^2=0 ?
The solutions to the equation 25-70X+49X^2=0 are X= 5/7
Find the zeros of 25-70X+49X^2=0
The zeros of 25-70X+49X^2=0 are X= 5/7