What are the solutions to the equation 8x^2+9x+1=0 ?

The solutions to the equation 8x^2+9x+1=0 are x=-1/8 ,x=-1

Find the zeros of 8x^2+9x+1=0

The zeros of 8x^2+9x+1=0 are x=-1/8 ,x=-1

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8 x^{2} + 9 x + 1 = 0

x = - \frac{1}{8}, x = - 1

Decimal Notation

x = - 0.125, x = - 1

Solution steps

8 x^{2} + 9 x + 1 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 9 \pm 9 ^{2} - 4 \cdot 8 \cdot 1}{2 \cdot 8}

9^{2} - 4 \cdot 8 \cdot 1 = 7

x_{1, 2} = \frac{- 9 \pm 7}{2 \cdot 8}

Separate the solutions

x_{1} = \frac{- 9 + 7}{2 \cdot 8}, x_{2} = \frac{- 9 - 7}{2 \cdot 8}

x = \frac{- 9 + 7}{2 \cdot 8} : - \frac{1}{8}

x = \frac{- 9 - 7}{2 \cdot 8} : - 1

The solutions to the quadratic equation are:

x = - \frac{1}{8}, x = - 1

2 x^{2} - x - 6 = 0

2 x^{2} + 3 x - 2 = - 4

(x - 3) (x - 2) 2 = 0

- 3 x^{2} = 8 x - 12

x^{2} + 20 x - 300 = 0

What are the solutions to the equation 8x^2+9x+1=0 ?
The solutions to the equation 8x^2+9x+1=0 are x=-1/8 ,x=-1
Find the zeros of 8x^2+9x+1=0
The zeros of 8x^2+9x+1=0 are x=-1/8 ,x=-1