What are the solutions to the equation completesquare x^2-x-1=0 ?

The solutions to the equation completesquare x^2-x-1=0 are x=(sqrt(5)+1)/2 ,x=(-sqrt(5)+1)/2

Find the zeros of completesquare x^2-x-1=0

The zeros of completesquare x^2-x-1=0 are x=(sqrt(5)+1)/2 ,x=(-sqrt(5)+1)/2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

x^{2} - x - 1 = 0

x = \frac{5 + 1}{2}, x = \frac{- 5 + 1}{2}

Decimal Notation

x = 1.61803 \dots, x = - 0.61803 \dots

Solution steps

x^{2} - x - 1 = 0

Move

1

to the right side

x^{2} - x = 1

Rewrite in the form

(x + a)^{2} = b

(x - \frac{1}{2})^{2} = \frac{5}{4}

For

the solutions are

f (x) = a, - a

Solve

x - \frac{1}{2} = \frac{5}{4} : x = \frac{5 + 1}{2}

Solve

x - \frac{1}{2} = - \frac{5}{4} : x = \frac{- 5 + 1}{2}

The solutions to the quadratic equation are:

x = \frac{5 + 1}{2}, x = \frac{- 5 + 1}{2}

3 x^{2} + 9 x + 5

x, x^{2} + y^{2} + (z - 5)^{2} = 25

6 x^{2} - 16 = 0

2 r^{2} + 6 r + 4 = 0

(x - 6)^{2} = 100

What are the solutions to the equation completesquare x^2-x-1=0 ?
The solutions to the equation completesquare x^2-x-1=0 are x=(sqrt(5)+1)/2 ,x=(-sqrt(5)+1)/2
Find the zeros of completesquare x^2-x-1=0
The zeros of completesquare x^2-x-1=0 are x=(sqrt(5)+1)/2 ,x=(-sqrt(5)+1)/2