What are the solutions to the equation x^2+144=24x ?

The solutions to the equation x^2+144=24x are x=12

Find the zeros of x^2+144=24x

The zeros of x^2+144=24x are x=12

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x^{2} + 144 = 24 x

x = 12

Solution steps

x^{2} + 144 = 24 x

Move

24 x

to the left side

x^{2} + 144 - 24 x = 0

Write in the standard form

a x^{2} + b x + c = 0

x^{2} - 24 x + 144 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 24 ) \pm ( - 24 ) ^{2} - 4 \cdot 1 \cdot 144}{2 \cdot 1}

(- 24)^{2} - 4 \cdot 1 \cdot 144 = 0

x_{1, 2} = \frac{- ( - 24 ) \pm 0}{2 \cdot 1}

x = \frac{- ( - 24 )}{2 \cdot 1}

\frac{- ( - 24 )}{2 \cdot 1} = 12

x = 12

The solution to the quadratic equation is:

x = 12

(x^{2} - 7) = 0

x^{2} - 10 x + 25

(- 5 z + 1) (- 9 z - 4) = 0

t, s = \frac{1}{2} a t^{2}

2 x^{2} - x = 4

What are the solutions to the equation x^2+144=24x ?
The solutions to the equation x^2+144=24x are x=12
Find the zeros of x^2+144=24x
The zeros of x^2+144=24x are x=12