What are the solutions to the equation x^2-x-18=-4x-4x ?

The solutions to the equation x^2-x-18=-4x-4x are x=2,x=-9

Find the zeros of x^2-x-18=-4x-4x

The zeros of x^2-x-18=-4x-4x are x=2,x=-9

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x^{2} - x - 18 = - 4 x - 4 x

x = 2, x = - 9

Solution steps

x^{2} - x - 18 = - 4 x - 4 x

Refine

x^{2} - x - 18 = - 8 x

Move

8 x

to the left side

x^{2} + 7 x - 18 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 7 \pm 7 ^{2} - 4 \cdot 1 \cdot ( - 18 )}{2 \cdot 1}

7^{2} - 4 \cdot 1 \cdot (- 18) = 11

x_{1, 2} = \frac{- 7 \pm 11}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 7 + 11}{2 \cdot 1}, x_{2} = \frac{- 7 - 11}{2 \cdot 1}

x = \frac{- 7 + 11}{2 \cdot 1} : 2

x = \frac{- 7 - 11}{2 \cdot 1} : - 9

The solutions to the quadratic equation are:

x = 2, x = - 9

16 x^{2} - 4 x + 3 = 0

2 x^{2} + x - 1 = 0

y^{2} + 2 y = 3

x^{2} + 5 x + 6 = 0

y^{2} + 49 = 0

What are the solutions to the equation x^2-x-18=-4x-4x ?
The solutions to the equation x^2-x-18=-4x-4x are x=2,x=-9
Find the zeros of x^2-x-18=-4x-4x
The zeros of x^2-x-18=-4x-4x are x=2,x=-9