What are the solutions to the equation a^2-6=a ?

The solutions to the equation a^2-6=a are a=3,a=-2

Find the zeros of a^2-6=a

The zeros of a^2-6=a are a=3,a=-2

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a^{2} - 6 = a

a = 3, a = - 2

Solution steps

a^{2} - 6 = a

Move

a

to the left side

a^{2} - 6 - a = 0

Write in the standard form

a x^{2} + b x + c = 0

a^{2} - a - 6 = 0

Solve with the quadratic formula

a_{1, 2} = \frac{- ( - 1 ) \pm ( - 1 ) ^{2} - 4 \cdot 1 \cdot ( - 6 )}{2 \cdot 1}

(- 1)^{2} - 4 \cdot 1 \cdot (- 6) = 5

a_{1, 2} = \frac{- ( - 1 ) \pm 5}{2 \cdot 1}

Separate the solutions

a_{1} = \frac{- ( - 1 ) + 5}{2 \cdot 1}, a_{2} = \frac{- ( - 1 ) - 5}{2 \cdot 1}

a = \frac{- ( - 1 ) + 5}{2 \cdot 1} : 3

a = \frac{- ( - 1 ) - 5}{2 \cdot 1} : - 2

The solutions to the quadratic equation are:

a = 3, a = - 2

\frac{2 a}{3 a}

9 x^{2} + 16 \geq 24 x

3 + 2 i

2 s^{2} - 7 s + 5

8 x^{2} + 48 x y + 72 y^{2}

What are the solutions to the equation a^2-6=a ?
The solutions to the equation a^2-6=a are a=3,a=-2
Find the zeros of a^2-6=a
The zeros of a^2-6=a are a=3,a=-2