What are the solutions to the equation 41^2=9^2+x^2 ?

The solutions to the equation 41^2=9^2+x^2 are x=40,x=-40

Find the zeros of 41^2=9^2+x^2

The zeros of 41^2=9^2+x^2 are x=40,x=-40

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4 1^{2} = 9^{2} + x^{2}

x = 40, x = - 40

Solution steps

4 1^{2} = 9^{2} + x^{2}

Switch sides

9^{2} + x^{2} = 4 1^{2}

Move

9^{2}

to the right side

x^{2} = 1600

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 1600, x = - 1600

1600 = 40

- 1600 = - 40

x = 40, x = - 40

6 x^{2} + 4 x + 11 = 0

18 q^{2} - 32 q = 7

x^{2} - 8 x + 4 = 0

x, 9 x^{2} - 16 y^{2} - 18 x - 64 y - 55 = 0

2 (x + 3) (x + 2) + 5 = (x + 3) (x + 1) + 6

What are the solutions to the equation 41^2=9^2+x^2 ?
The solutions to the equation 41^2=9^2+x^2 are x=40,x=-40
Find the zeros of 41^2=9^2+x^2
The zeros of 41^2=9^2+x^2 are x=40,x=-40