What are the solutions to the equation x^2-5=-4x ?

The solutions to the equation x^2-5=-4x are x=1,x=-5

Find the zeros of x^2-5=-4x

The zeros of x^2-5=-4x are x=1,x=-5

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x^{2} - 5 = - 4 x

x = 1, x = - 5

Solution steps

x^{2} - 5 = - 4 x

Move

4 x

to the left side

x^{2} - 5 + 4 x = 0

Write in the standard form

a x^{2} + b x + c = 0

x^{2} + 4 x - 5 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 \cdot 1 \cdot ( - 5 )}{2 \cdot 1}

4^{2} - 4 \cdot 1 \cdot (- 5) = 6

x_{1, 2} = \frac{- 4 \pm 6}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 4 + 6}{2 \cdot 1}, x_{2} = \frac{- 4 - 6}{2 \cdot 1}

x = \frac{- 4 + 6}{2 \cdot 1} : 1

x = \frac{- 4 - 6}{2 \cdot 1} : - 5

The solutions to the quadratic equation are:

x = 1, x = - 5

5 x^{2} - 60 = 20

3 x^{2} = - 4 + 8 x

(x - 1)^{2} + 11 x - 199 = 3 x^{2} - (x - 2)^{2}

12.835 = y ((11.1294 - 3.65 y) + 1.5 y)

16 x^{2} - 18 = 7

What are the solutions to the equation x^2-5=-4x ?
The solutions to the equation x^2-5=-4x are x=1,x=-5
Find the zeros of x^2-5=-4x
The zeros of x^2-5=-4x are x=1,x=-5