What are the solutions to the equation 2+x^2=x+2 ?

The solutions to the equation 2+x^2=x+2 are x=1,x=0

Find the zeros of 2+x^2=x+2

The zeros of 2+x^2=x+2 are x=1,x=0

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2 + x^{2} = x + 2

x = 1, x = 0

Solution steps

2 + x^{2} = x + 2

Move

2

to the left side

x^{2} = x

Move

x

to the left side

x^{2} - x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 1 ) \pm ( - 1 ) ^{2} - 4 \cdot 1 \cdot 0}{2 \cdot 1}

(- 1)^{2} - 4 \cdot 1 \cdot 0 = 1

x_{1, 2} = \frac{- ( - 1 ) \pm 1}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 1 ) + 1}{2 \cdot 1}, x_{2} = \frac{- ( - 1 ) - 1}{2 \cdot 1}

x = \frac{- ( - 1 ) + 1}{2 \cdot 1} : 1

x = \frac{- ( - 1 ) - 1}{2 \cdot 1} : 0

The solutions to the quadratic equation are:

x = 1, x = 0

5 x^{2} + 245 = 0

- 3 = 2 - y^{2} - y

3 (x + 8)^{2} + 261 = 111

x, 12 x^{2} - 3 x y - 6 y^{2} = 0

a^{2} + 2 4^{2} = 2 6^{2}

What are the solutions to the equation 2+x^2=x+2 ?
The solutions to the equation 2+x^2=x+2 are x=1,x=0
Find the zeros of 2+x^2=x+2
The zeros of 2+x^2=x+2 are x=1,x=0