What are the solutions to the equation 6x^2-84x+240=0 ?

The solutions to the equation 6x^2-84x+240=0 are x=10,x=4

Find the zeros of 6x^2-84x+240=0

The zeros of 6x^2-84x+240=0 are x=10,x=4

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6 x^{2} - 84 x + 240 = 0

x = 10, x = 4

Solution steps

6 x^{2} - 84 x + 240 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 84 ) \pm ( - 84 ) ^{2} - 4 \cdot 6 \cdot 240}{2 \cdot 6}

(- 84)^{2} - 4 \cdot 6 \cdot 240 = 36

x_{1, 2} = \frac{- ( - 84 ) \pm 36}{2 \cdot 6}

Separate the solutions

x_{1} = \frac{- ( - 84 ) + 36}{2 \cdot 6}, x_{2} = \frac{- ( - 84 ) - 36}{2 \cdot 6}

x = \frac{- ( - 84 ) + 36}{2 \cdot 6} : 10

x = \frac{- ( - 84 ) - 36}{2 \cdot 6} : 4

The solutions to the quadratic equation are:

x = 10, x = 4

x^{2} + 10 x + 44 = 0

x, 2 x^{2} + x y - y^{2} = 2

8 x^{2} - 65 x + 8 = 0

x^{2} + 8 x - 105 = 0

x^{2} + x^{2} = 3^{2}

What are the solutions to the equation 6x^2-84x+240=0 ?
The solutions to the equation 6x^2-84x+240=0 are x=10,x=4
Find the zeros of 6x^2-84x+240=0
The zeros of 6x^2-84x+240=0 are x=10,x=4