What are the solutions to the equation -5x-13+7x^2=3x^2 ?

The solutions to the equation -5x-13+7x^2=3x^2 are x=(5+sqrt(233))/8 ,x=(5-sqrt(233))/8

Find the zeros of -5x-13+7x^2=3x^2

The zeros of -5x-13+7x^2=3x^2 are x=(5+sqrt(233))/8 ,x=(5-sqrt(233))/8

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

- 5 x - 13 + 7 x^{2} = 3 x^{2}

x = \frac{5 + 233}{8}, x = \frac{5 - 233}{8}

Decimal Notation

x = 2.53304 \dots, x = - 1.28304 \dots

Solution steps

- 5 x - 13 + 7 x^{2} = 3 x^{2}

Move

3 x^{2}

to the left side

- 5 x - 13 + 4 x^{2} = 0

Write in the standard form

a x^{2} + b x + c = 0

4 x^{2} - 5 x - 13 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 5 ) \pm ( - 5 ) ^{2} - 4 \cdot 4 ( - 13 )}{2 \cdot 4}

(- 5)^{2} - 4 \cdot 4 (- 13) = 233

x_{1, 2} = \frac{- ( - 5 ) \pm 233}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- ( - 5 ) + 233}{2 \cdot 4}, x_{2} = \frac{- ( - 5 ) - 233}{2 \cdot 4}

x = \frac{- ( - 5 ) + 233}{2 \cdot 4} : \frac{5 + 233}{8}

x = \frac{- ( - 5 ) - 233}{2 \cdot 4} : \frac{5 - 233}{8}

The solutions to the quadratic equation are:

x = \frac{5 + 233}{8}, x = \frac{5 - 233}{8}

2 x^{2} + x - 20 = 0

t, s = \frac{1}{2} g t^{2} + v t

X^{2} - X - 2 = 0

4 t^{2} - 9 = 0

x^{2} + \frac{3}{2} x - \frac{1}{2} = 0

What are the solutions to the equation -5x-13+7x^2=3x^2 ?
The solutions to the equation -5x-13+7x^2=3x^2 are x=(5+sqrt(233))/8 ,x=(5-sqrt(233))/8
Find the zeros of -5x-13+7x^2=3x^2
The zeros of -5x-13+7x^2=3x^2 are x=(5+sqrt(233))/8 ,x=(5-sqrt(233))/8